Answer:
See below.
Explanation:
Let's first find the equation of the smallest circle. We know the center is at (-4,3) and the radius is 3 units. Recall the equation for a circle:
![(x-h)^2+(y-k)^2=r^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3gezmntbbjw0kxpks4y5gde90ue9dh956u.png)
Where (h,k) is the center and r is the radius.
Plugging the numbers in, we get:
![(x-(-4))^2+(y-3)^2=3^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/b1jifcab610rrru1pbxooutplq8xogby3t.png)
![(x+4)^2+(y-3)^2=9](https://img.qammunity.org/2021/formulas/mathematics/high-school/ucg08hfuez4b061x0azetisrorwf0dgcun.png)
Each subsequent circle's radius is 4 units greater than the smallest circle. Importantly, note that the center will remain unchanged. The largest circle will have a radius of 3 + 4 + 4 + 4 = 15. We simply need to change the r:
![(x+4)^2+(y-3)^2=15^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/67oz36vgyfd8gra3hcuhth2wa5cd0lytu5.png)
Thus, equation for the fourth circle is:
![(x+4)^2+(y-3)^2=225](https://img.qammunity.org/2021/formulas/mathematics/high-school/x9or2qs50m9p37nzmbdbxkakuanycfo7so.png)