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Find the area of triangle whose vertices are (- 8,4 )(- 6,6) and (- 3,9)​

User Ohid
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1 Answer

4 votes

Answer:

Area of the triangle = 0

Explanation:

We are given the vertices of a triangle as: (- 8,4 ), (- 6,6), (- 3,9)​

The formula to find the Area of the triangle =

1/2[ x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)]

Where :

(x₁, y₁) = (- 8,4 )

(x₂, y₂) = (- 6,6)

(x₃, y₃) = (- 3,9)

Area of the triangle = 1/2[-8(6 - 9) + -6(9 - 4) + -3(4 - 6)]

= 1/2[ (-8 × -3) +( -6 × 5) +( -3× -2)]

= 1/2[ 24 - 30 + 6)

= 1/2[ 24 + 6 - 30]

= 1/2 [30 - 30]

=1/2[ 0 ]

= 0

Therefore, the area of triangle whose vertices are (- 8,4 ), (- 6,6) and (- 3,9)​ is ZERO( = 0 )

User Erwan
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