Answer:
The right solution will be the "2v".
Step-by-step explanation:
For something like an object underneath pure rolling the speed at any point is calculated by:
⇒

Although the angular velocity was indeed closely linked to either the transnational velocity throughout particular instance of pure rolling as:
⇒

Significant meaning is obtained, as speeds are in the same direction. Therefore the speed of rotation becomes supplied by:
⇒

On substituting the estimated values, we get
⇒

⇒

So that the velocity will be:
⇒

⇒
