Question

At what pressure would 11.1 moles of a gas occupy 44.8 L at 300 K?

Answer 1

`P=6.10atm`

Step-by-step explanation:

Hello,

In this case, we can study the ideal gas equation that relates temperature, volume, pressure and moles as shown below:

`PV=nRT`

Thus, since we are asked to compute the pressure y simply solve for it as follows:

`P=(nRT)/(V)=(11.1mol*0.082(atm*L)/(mol*K)*300K)/(44.8L)\\ \\P=6.10atm`

Best regards.