Answer:
A) 2/3
B) 4 sqrt 30/9 = y
C) P= 3/4 * sqrt 2
Explanation:
A.) A = K*B
1= K * 3
K = 1/3
Now we will find the unknown A value
A = 1/3 * 2
A= 2/3
B) x=k* y^2
27 = k * 4^2
K= 27/16
Now , we will find the unknown value of y
10= 27/16 * y^2
10*16/27 = y^2
Sqrt of 160/27 =y
4 sqrt 10/3 sqrt 3 =y
4 sqrt 30/9 = y
C) p = k * sqrt Q
3= k * sqrt 16
3 = k * 4
K= 3/4
Now, when we substitute the value of k in to the variation
P= 3/4 * sqrt 2