Question

-2x(x+3)-(x+1)(x-2)=

Answer 1

`\huge\boxed{-2x(x+3)-(x+1)(x-2)=-3x^2-5x+2}`

Explanation:

`-2x(x+3)-(x+1)(x-2)`

Use the distributive property: a(b + c) = ab + ac

and FOIL: (a + b)(c + d) = ac + ad + bc + bd

`=(-2x)(x)+(-2x)(3)-\bigg[(x)(x)+(x)(-2)+(1)(x)+(1)(-2)\bigg]\\\\=-2x^2-6x-\bigg(x^2-2x+x-2\bigg)=-2x^2-6x-x^2-(-2x)-x-(-2)\\\\=-2x^2-6x-x^2+2x-x+2`

Combine like terms:

`=(-2x^2-x^2)+(-6x+2x-x)+2=-3x^2+(-5x)+2\\\\=-3x^2-5x+2`

Answer 2

-3x^2 -5x +2

Explanation:

-2x(x+3)-(x+1)(x-2)=

Distribute

-2x^2 -6x -(x+1)(x-2)

Foil

-2x^2 -6x -(x^2 -2x +x -2)

Combine like terms

-2x^2 -6x -(x^2 -x -2)

Distribute the minus sign

-2x^2 -6x -x^2 +x +2

Combine like terms

-2x^2 -x^2 -6x +x +2

-3x^2 -5x +2