Question

If the primary voltage of a transformer is 230V and the primary coil is 80. Calculate the secondary voltage when the secondary turn is 160. *Ans 460 volts*

Answer 1

`V_(out) = 460`

Step-by-step explanation:

From your question, you already posted the answer

However, I'll give the steps to get the answer

Given

`Primary\ Voltage = 230V`

`Primary\ Coil = 80`

`Secondary\ Coil = 160`

Required

Secondary Voltage

The relationship between the primary voltage, secondary voltage, turns of primary coil and secondary coil is as follows;

`(V_(out))/(V_(in)) = (N_(s))/(N_(p))`

Where

`V_(in) = Primary\ Voltage = 230V`

`V_(out) = Secondary\ Voltage = ??`

`N_(p) = Primary\ Coil = 80`

`N_(s) = Secondary\ Coil = 160`

Substitute these values in the formula above;

`(V_(out))/(V_(in)) = (N_(s))/(N_(p))`

becomes

`(V_(out))/(230) = (160)/(80)`

`(V_(out))/(230) = 2`

Multiply both sides by 230

`230 * (V_(out))/(230) = 2 * 230`

`V_(out) = 2 * 230`

`V_(out) = 460`

Hence, the secondary voltage is 460 Volts