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Find the y-intercept and the axis of symmetry of f(x)=ax2+2ax+3.

User Anmol
by
9.3k points

1 Answer

6 votes

Answer:


y= cx^2 +dx +e

We see that:


c = a, d= 2a , e= 3

The axis of symmetry is defined by this formula:


X= - (d)/(2c)

And replacing we got:


X= -(2a)/(2a)= -1

Thn the axis of symmetry would be X=-1

Explanation:

For this case we have the following function:


y = ax^2 +2ax +3

If we compare this function with the general expression of a quadratic formula given by:


y= cx^2 +dx +e

We see that:


c = a, d= 2a , e= 3

The axis of symmetry is defined by this formula:


X= - (d)/(2c)

And replacing we got:


X= -(2a)/(2a)= -1

Thn the axis of symmetry would be X=-1

User Brett Duncavage
by
7.6k points

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