Question

A submarine is 58.8 m from a whale. The sub sends out a sonar ping to locate the whale. The speed of sound underwater is 1520 m/s. How much time does it take for the sound wave to travel to the whale and back? (Unit = s)

Answer 1

0.08

Step-by-step explanation:

this problem assume that both of whale and submarine are in rest position or in constant linier motion in same direction and same speed.

The sound will travel from Submarine to the whale and back again to submarine. so the time will be like this

t = 2d/v

t = 2*58.8/1520

t = 117.6/1520

t = 0.077368 s

t ≈ 0.08 s (less then 1 s)

Answer 2

0.0774s

Step-by-step explanation:

The formula to find the time of an echo is time = (2)(distance) / (velocity)

So plug in the numbers to the formula

(2)(58.8) / (1520)

= 0.0774s