Question

Suppose a 22.092 g sample of a 1:1 mixture of acetylferrocene and ferrocene was separated by column chromatography, and the recovered fractions weighed 9.017 g (acetylferrocene) and 8.075 g (ferrocene), what was the percent recovery of acetylferrocene?

Answer 1

81.6%

Step-by-step explanation:

mass of acetylferrocene and ferrocene mixture = 22.092 g

mass ratio acetylferrocene and ferrocene mixture = 1 : 1

The sum of the ratios = 2, therefore the mass of each compound will be half the mass of the mixture

mass of each compound in the sample mixture = 1/2 * 22.09 2= 11.046 g

mass of recovered acetylferrocene = 9.017 g

percentage recovery = mass recovered/mass in sample * 100%

percentage recovery of acetylferrocene = (9.017 g / 11.046 g) * 100%

percentage recovery of acetylferrocene = 81.6%