Answer:
speed while going = 42, while returning home = 28
Explanation:
let his speed on the way to his parents house is (x)
then his speed while returning is x - 14
Time = Distance / speed
528 / x + 528 / x -14 = 22
multiplying the denominator ...
528x + 528x +7392 = 22x^2 +14x
1056x + 7392 = 22x^2 + 308x
0 = 22x^2 -748x -7392
"dividing by 22"
0 = x^2 -34x-336
0 = (x+8) (x-42)
x must be 42
finally jon's speed while back home is 42 - 14 = 28