Question

what is the balanced equation when copper metal is placed in a solution when platnium ii chloride is placed. what is the equation

Answer 1

`Cu~+~PtCl_2->Pt~+~CuCl_2`

Step-by-step explanation:

In this case, we can start with the formula of Platinum (II) Chloride. The cation is the atom at the left of the name (in this case
`Pt^+^2`) and the anion is the atom at the right of the name (in this case
`Cl^-`). With this in mind, the formula would be
`PtCl_2`.

Now, if we used metallic copper we have to put in the reaction only the copper atom symbol
`Cu`. So, we have as reagents:

`Cu~+~PtCl_2->`

The question now is: What would be the products? To answer this, we have to remember "single displacement reactions". With a general reaction:

`A~+~BC->AB~+~C`

With this in mind, the reaction would be:

`Cu~+~PtCl_2->Pt~+~CuCl_2`

I hope it helps!