Question

Let
`p=x^(2)+6`

Which equation is equivalent to
`(x^(2)+6)^(2)-21=4x^(2)+24` in terms of
`p`?

Answer 1

Hello There. ☆~---~--___●♡●__~--☆ Since p = x² - 7, you can substitute/plug in p for x² - 7

So:

(x² - 7)² - 4x² + 28 = 5

(p)² - 4x² + 28 = 5 You can factor out -4 from (-4x² + 28)

p² - 4(x² - 7) = 5 Plug in p

p² - 4p = 5 Subtract 5

p² - 4p - 5 = 0 And, your correct answer is C.

Hope It Helps!~

ItsNobody~ ☆