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A car engine burns gas at 495 K and exhausts to the air at 293 K. What is the highest possible efficiency it could have?

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A car engine burns gas at 495 K and exhausts to the air at 293 K. What is the highest-example-1
User Cjay
by
5.6k points

2 Answers

0 votes

Answer:

0.41

Step-by-step explanation:

Trust me bro

User Harbinja
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6.3k points
5 votes

Answer:

59.19%

Step-by-step explanation:

Step 1:

Data obtained from the question. This include the following:

Input temperature = 495 K.

Output temperature = 293 K.

Efficiency =..?

Step 2:

Determination of the efficiency of the engine.

Efficiency is simply defined as the ratio of output to input times 100. Mathematically, it is expressed as:

Efficiency = output /input x 100

With the above formula, we can calculate the efficiency of the engine as follow:

Input temperature = 495 K.

Output temperature = 293 K.

Efficiency =..?

Efficiency = output /input x 100

Efficiency = 293/495 x 100

Efficiency = 59.19%

Therefore, the efficiency of the engine is 59.19%

User Sylnois
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5.9k points