Answer:
0.03333 or 1/30
Explanation:
Let A =" I go sailing" and B = "it does not rain"
P(A) = 0.03
P(B) =0.90
Since I never go sailing when it rains, P(A and B) =0.03.
Therefore, the (conditional) probability that I go sailing, given that it does not rain is:
![P(A|B)=(P(A\ and\ B))/(P(B)) \\P(A|B)=(0.03)/(0.90)=0.033333](https://img.qammunity.org/2021/formulas/mathematics/high-school/3zow2d39ckca2d3fgr26b0kgd3gk2m00uk.png)
The probability is 0.03333 or 1/30.