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Which point satisfies the system of equations y = 3x − 2 and y = -2x + 3? PLEASE I NEED IT NOW

User Mdashx
by
6.7k points

2 Answers

3 votes

Answer:

(1,1) or x=1 and y=1

Explanation:

Since both equations are equal to y you can use substitution, replacing he y in y=3x-2 with -2x+3, giving you the equation -2x+3=3x-2. We can use this to solve for x. To isolate the variable you first need to add 2 to both sides, giving you -2x+5=3x, then add 2x to both sides. This gives you 5=5x, lastly you need to divide both sides by 5 to get x=1. Now you can plug x(1) into 1 of the 2 given equations to find y, I'll use y=3x-2. When x is plugged in as 1 you get the equation y=3(1)-2, after multiplying you get y=3-2, then you subtract to get y=1. In order to make sure this is the correct solution you can also plug in x as 1 and now y as 1 into the other equation, y=-2x+3. We can plug 1 in for x and solve for -2(1)+3 to get -2+3, or 1, so y is 1 for both equations, therefore the solution we got was correct, x=1 and y=1, or (1,1).

User David Pine
by
6.4k points
5 votes

Answer:

(1,1)

Explanation:

y = 3x − 2

y = -2x + 3

the point that satisfies the system:

when the two functions are equal

3x-2=-2x+3

3x+2x=3+2

5x=5

x=5/5=1

when x=1

y=-2x+3

y=-2(1)+3

y=1

Which point satisfies the system of equations y = 3x − 2 and y = -2x + 3? PLEASE I-example-1
User Vikash Pareek
by
6.7k points
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