Answer:
W =1562.53 N
Step-by-step explanation:
It is given that,
Radius of the aluminium ball, r = 24 cm = 0.24 m
The density of Aluminium,
![d=2698.4\ kg/m^3](https://img.qammunity.org/2021/formulas/physics/high-school/uc3zsjvd2dp9yex8wwwm3txpd57qdstshz.png)
We need to find the thrust and the force. The mass of the liquid displaced is given by :
![m=dV](https://img.qammunity.org/2021/formulas/physics/high-school/6ohb42040khuh8gxhk4pvnhe84q8xfenbn.png)
V is volume
Weight of the displaced liquid
W = mg
![W=dVg](https://img.qammunity.org/2021/formulas/physics/high-school/urfgy8yb0iy7leqff679p8ntz4t1ubit81.png)
So,
![W=dg* (4)/(3)\pi r^3\\\\W=2698.4* 10* (4)/(3)* \pi * (0.24)^3\\\\W=1562.53\ N](https://img.qammunity.org/2021/formulas/physics/high-school/3rwhy0immpj0v88q7yl3md1to8ifoo1ly7.png)
So, the thrust and the force is 1562.53 N.