Question

what is the coordinate of the vertex of the parabola y-2=1/12(x+10) a. ( 10,-2) b. (-10,2) c. (-2,10) d. (2.-10)

Answer 1

`y-a= c(x-b)^2`

With the vertex
`V= (b,a)`

We see that b = -10 and a = 2 and then the vertes wuld be:

`V= (-10,2)`

And the best option is:

b. (-10,2)

Explanation:

For this problem we have the following function:

`y-2 = (1)/(2) (x+10)`

And if we compare this expression with the general expression for a parabola given by:

`y-a= c(x-b)^2`

With the vertex
`V= (b,a)`

We see that b = -10 and a = 2 and then the vertes wuld be:

`V= (-10,2)`

And the best option is:

b. (-10,2)