Answer:
0.3110
Explanation:
This is a binomial distribution with probability of success (being a chemistry major) p = 0.40.
The general formula for a binomial distribution is:
![P(x=k)=(n!)/((n-k)!k!)*p^k*(1-p)^(n-k)](https://img.qammunity.org/2021/formulas/mathematics/college/pzqtu97h0zuuh2i7a2ib7ehzcdw14z9air.png)
Where n is the sample size and k is the desired number of successes.
The probability of k=2 in a sample of n =6 is:
![P(x=2)=(6!)/((6-2)!2!)*0.4^2*(1-0.4)^(6-2) \\P(x=2)=(6!)/((6-2)!2!)*0.4^2*(1-0.4)^(6-2)\\P(x=2)=3*5*0.4^2*0.6^4\\P(x=2)=0.3110](https://img.qammunity.org/2021/formulas/mathematics/college/en4u11bzia4e1dtiuin6djih3zhiex25s4.png)
The probability is 0.3110