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Which is the distance betweeen parallel lines with the equations 3x - 5y = 1 and 3x-5y=-3

2 Answers

0 votes

Answer:

The Answer is C. The person above is almost correct, but they did not simplify to 2sqrt34/17

Explanation:

User Salius
by
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4 votes

Answer:

Distance between the two parallel lines


d = (4)/(√(34) ) = 0.6859

Explanation:

Step(i):-

Given the two equations are 3 x - 5 y = 1 ...(i)

and 3 x - 5 y = - 3....(ii)

Distance between the two parallel lines


d = \fracC_(1) - C_(2) {\sqrt{a^(2)+b^(2) } }

Given equations

a = 3 , b = -5 and C₁ = 1 and C₂ = -3

Step(ii):-

Distance between the two parallel lines


d = \fracC_(1) - C_(2) {\sqrt{a^(2)+b^(2) } }


d = (|1 - (-3)| )/(√(9+25 ) )


d = (4)/(√(34) )

Final answer:-

Distance between the two parallel lines


d = (4)/(√(34) )

User Alphazwest
by
5.3k points