Answer:
frequency of h dominant = 16%
Frequency of heterozygotes = 48%
Step-by-step explanation:
The computation of frequency of h dominants and heterozygotes in your population is shown below:
Since it is mentioned that
q^2 = 36%
So q = 0.6
And
p + q = 1
So, the p is 0.4
Now the frequency of h dominant is
= p^2
= (0.4)^2
= 16%
And, the heterozygotes in the population is
= 2 × p × q
= 2 × 0.4 × 0.6
= 48%