Question

What is the length of the transverse axis of the conic section shown below?

(y+2)^2/25 - (x-3)^2/4=1

Answer 1

Length of transverse axis = 2 b = 10

Length of conjugate axis = 2 a = 4

Explanation:

Explanation:-

Given Hyperbola

`((y+2)^(2) )/(25) -((x-3)^(2) )/(4) =1`

Standard form of Hyperbola

`((y-(K))^(2) )/(b^(2) ) -((x-h)^(2) )/(a^(2) ) =1`

Center (h , k ) = (3 , -2 ) , a = 2 and b = 5

Length of transverse axis = 2 b = 2(5) = 10

Length of conjugate axis = 2 a = 2 (2) = 4