Question

`20+3x-15+x=27`

Answer 1

`\boxed{\sf x = (11)/(2)}`

Explanation:

`\sf Solve \: for \: x: \\ \sf \implies 20 + 3x - 15 + x = 27 \\ \\ \sf Grouping \: like \: terms, \: 20 + 3x - 15 + x = \\ \sf (3x + x) + (20 - 15) : \\ \sf \implies \boxed{ \sf (3x + x) + (20 - 15)} = 27 \\ \\ \sf 3x + x = 4x : \\ \sf \implies \boxed{ \sf 4x} + (20 - 15) = 27 \\ \\ \sf 20 - 15 = 5 : \\ \sf \implies 4x + \boxed{ \sf 5} = 27 \\ \\ \sf Subtract \: 5 \: from \: both \: sides: \\ \sf \implies 4x + (5 - \boxed{ \sf 5}) = 27 - \boxed{ \sf 5} \\ \\ \sf 5 - 5 = 0 : \\ \sf \implies 4x = 27 - 5 \\ \\ \sf 27 - 5 = 22 : \\ \sf \implies 4x = \boxed{ \sf 22} \\ \\ \sf Divide \: both \: sides \: of \: 4x = 22 \: by \: 4 : \\ \sf \implies (4x)/(4) = (22)/(4) \\ \\ \sf \frac{ \cancel{4}}{ \cancel{4}} = 1 : \\ \sf \implies x = (22)/(4) \\ \\ \sf \implies x = \frac{11 * \cancel{2}}{2 * \cancel{2}} \sf \implies x = (11)/(2)`

Answer 2

x=11/2

Explanation:

First we can combine similar terms on the left side. 3x + x is 4x and 20-15 is 5

Now that we have combined them, we are left with 4x+5=27

Subtract 5 on both sides to cancel out the 5.

4x=22

Divide both sides by 4

x=22/4

Simplify

x=11/2