Question

G(n)=80×(3/4)^n
complete the recursive formula of g(n)
g(1)=
g(n)= g(n-1) ×

Answer 1

Explanation:

Hello,

`g(n)=80*((3)/(4))^n \ So\\g(1)=80*(3)/(4)=20*3=60 \\\\ and \\\\(g(n))/(g(n-1))=(80*((3)/(4))^n)/(80*((3)/(4))^(n-1))=(3)/(4) \ so \\\\g(n)=g(n-1)*(3)/(4)`

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