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A box is filled with 9 red crayons, 2 blue crayons, and 5 yellow crayons. A crayon is chosen at random from the box. Find the probability that it is a red or a blue crayon. Write your answer as a fraction in simplest form.

User Anre
by
7.2k points

1 Answer

5 votes

Answer:


P(Red\ or\ Blue) = (11)/(16)

Explanation:

Given


Red = 9


Blue = 2


Yellow = 5

Required

Probability of Red or Blue

First, it should be noted that the event described in the question are mutually exclusive or disjoint events;

Meaning that the probability of one have no effect the other;

Having said that; the Probability of Red ot Blue is as follows


P(Red\ or\ Blue) = P(Red) + P(Blue)

Calculating
P(Blue)


P(Blue) = Number\ of\ blue\ crayon / total\ crayon


P(Blue) = (2)/(9+ 2 + 5)


P(Blue) = (2)/(16)

Calculating
P(Red)


P(Red) = Number\ of\ red\ crayon / total\ crayon


P(Red) = (9)/(9+ 2 + 5)


P(Red) = (9)/(16)

Substitute these values in the formula given above


P(Red\ or\ Blue) = P(Red) + P(Blue)


P(Red\ or\ Blue) = (9)/(16) + (2)/(16)

Take LCM


P(Red\ or\ Blue) = (9 + 2)/(16)


P(Red\ or\ Blue) = (11)/(16)

Hence, the probability of a red or blue crayon is


P(Red\ or\ Blue) = (11)/(16)

User Drch
by
7.5k points
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