Answer:
9 foot.
Explanation:
From the question given, we were told that a 300-pound weight and a 450-pound weight are placed on each end of a 15-foot bar.
The diagram illustrating the question can be seen on the attached photo.
Weight 1 (W1) = 300 pound
Weight 2 (W2) = 450 pound.
Distance to which the fulcrum must be placed in order to balance (d1) = x
Distance from the other side of the bar (d2) = 15 – x
W1d1 = W2d2
300 × x = 450 (15 – x)
Clear bracket
300x = 6750 – 450x
Collect like terms
300x + 450x = 6750
750x = 6750
Divide both side by the coefficient of x i.e 750
x = 6750/750
x = 9 foot.
Therefore, the fulcrum must be placed at 9 foot in order to balance the bar.