Question

(3a^3-5b^3)+blank a^3+blank b^3=(a^3+b^3)

Answer 1

(3a³-5b³)+ (-2)a³ +6b³=(a³+b³)

Explanation:

First, lets remove the brackets. There is no "-" before the brackets, so we can just remove them at all.

3a³-5b³+ ...a³ +...b³=a³+b³

Now we can joint similar monoms (with variable a) ( and with variable b) in the left side of equation

3a³+...a³ -5b³ +...b³=a³+b³

Now we can notice that 3a³+...a³=a³ (1) and

-5b³ +...b³=b³ (2)

Lets find deduct 3a³ from both sides of (1)

...a³= a³-3a³

...a³= -2a³ So instead ... we have to type -2 (-2 is negative sowe type -2 in brackets).

Similarly lets add 5b³ to both sides of (2)

-5b³ +...b³=b³

-5b³ +5b³ +...b³=b³+5b³

...b³=6b³ So instead ... we have to type 6.