Answer:
1 /√( 1 - x^2).
Explanation:
y = arcsin x
x = sin y
dx/dy = cos y
dy/dx = 1 / cos y
Now cos y = √( 1 - sin^2 y)
but sin y = x so
cos y = √( 1 - x^2).
So dy/dx = 1 / √( 1 - x^2).
f'(x)=
As khown the derivative of arcsin(x) is;
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