Question

A fish population grew according to the following quadratic model, the number of fish a day is given by

P(t)=800t-t^2

What is the growth rate at t=600​

Answer 1

-400

Explanation:

We can find the rate of change by differentiating the population function:

P'(t) = 800 -2t

Then at t = 600, the growth rate is ...

P'(600) = 800 -2(600) = -400

The growth rate is -400 fish per day on day 600.