Question

Find the equation of a line that passes through the point (0, -2) and is parallel to a line that goes through the points (4, 0) and (0, 3)

Answer 1

y = (-3/4)x -2

or: y = -0.75x -2

Explanation:

First, find the slope of the line that it parallel to. Using equation

slope m = (y2-y1)/(x2-x1),

slope of line that passes through points (4, 0) and (0, 3)

= (3 - 0) /( 0-4)

= -3/4

Since the lines are parallel, both of them have the same slope, which is -3/4.

The point (0, -2) is actually the point of y -intercept (c) of the new line, so we can simply use the slope-intercept form to find the equation of line.

y = mx + c

y = (-3/4)x + (-2)

y = (-3/4)x -2