Question

How much force does it take to bring a 1,050 N car from rest to a velocity of 42 m/s in 13 seconds?

Answer 1

F = 339.23 N

Step-by-step explanation:

Weight of a car, W = 1050 N

Initial velocity, u = 0

Final velocity, v = 42 m/s

Time, t = 13 s

The weight of an object is given by :

W = mg

g is the acceleration due to gravity

`m=(W)/(g)\\\\m=(1050)/(10)\\\\m=105\ kg`

The force acting on car is :

`F=ma\\\\F=(m(v-u))/(t)\\\\F=(105* (42-0))/(13)\\\\F=339.23\ N`

So, the force acting on the car is 339.23 N.