Question

in 2016 the members of a club paid a total of 42 in subscription fees.In 2017,the number of members were increased by 20 and the subscription fees were subsequently reduced by 10 cents per member.the total of the subscription fees for 2017 was 45.How many members were there in 2016?

Answer 1

70 members in 2016

Explanation:

In 2016

Let the number of members= x

They all paid y amount

Total fees= 42

Xy= 42...... equation 1

In 2017

Members= x+20

They paid y-0.1

Total fees = 45

(X+20)(y-0.1)= 45…equation 2

Xy -0.1x +20y -2= 45

Using values from equation 1

42-0.1(42/y) +20y -2= 45

-4.2/y+20y-5= 0

20y² -4.2 -5y = 0

100y² -25y -21= 0

Solving quadratically

Y= 0.6 or -0.35

We are dealing with price so y Is

definitely a positive number

Y= 0.6

If y= 0.6

Solving for x

Xy= 42

X= 42/0.6

X=70

There were exactly 70 members in 2016