Question

Please help, the topic is similarity 2d shapes :))

Answer 1

`30 {cm}^(2)`

Solution,

`(bd)/(cd) = (ae)/(ce)`

`(6)/(8) = (9)/(8 + de)`

`48 + 6(de) = 72`

`6(de) = 72 - 48`

`6(de) = 24`

`de = (24)/(4)`

`de = 4 \:`

CE = 8 + 4 = 12

Area of trapezoid ABDE:

Area of ∆ AEC - Area of ∆ BDC

`= (1)/(2) * 9 * 12 - (1)/(2) * 6 * 8`

`= 54 - 24`

`= 30 \: {cm}^(2)`

Hope this helps...

Good luck on your assignment...