Answer:
About 110 g
Step-by-step explanation:
The solubility graph is a very useful tool because it tells you the amount of potassium nitrate that can be dissolved per
100 mL
of water in order to have a saturated solution of potassium nitrate at a given temperature.
In order to find the solubility of the salt at 60 degree celcius
start from the 60 degree celcius
Mark on the graph and move up until you intersect the curve. At the point of intersection, move left until you intersect the y axis and read off the value that you land on.
In this case, you can estimate that the solubility of potassium nitrate in water at 60 degree celcius is equal to about
solubility ≈ 110 g / 100 mL water
−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−
This tells you that a saturated solution of potassium nitrate will hold about
110 g of dissolved salt, i.e. of dissociated salt, per 100 ml of water at 60 degree celcius