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A train station bell gives off a fundamental tone of 505 Hz as the train approaches the station at a speed of 27.6 m/s. If the speed of sound in air on that day is 339 m/s, what will be the apparent frequency of the bell to an observer riding the train

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Answer:

Apparent frequency of the bell to the observer is 546.12 Hz

Step-by-step explanation:

The frequency of train bell (frequency of source) = 505 Hz

The speed of train (observer) = 27.6 m/s

The speed of sound in the air is (velocity of sound) = 339 m/s

The apparent frequency of the bell to the observer is calculated as follows:

Apparent frequency of bell to the observer.


= \text{frequency of source} * (Observer + velocity \ of \ sound )/( velocity \ of \ sound ) \\= 505 * (27.6 + 339)/(339) \\= 546.12 Hz

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