Question

What quantity of electricity

will liberate 0.125 more
of oxygen molecules during
the electrolysis of dilute
sodium chloride solution (f=
96500cmol)​

Answer 1

96500 C

Step-by-step explanation:

The equation of the electrolytic process is;

4OH^-(aq) -----> 2H2O(l) +O2(g) + 4e

From the reaction equation; one mole of oxygen is liberated by 4 moles of electrons.

If one mole of electrons= 96500 Cmol-1, then;

1 mole of oxygen is liberated by 4×96500 Cmol-1

0.25 moles of oxygen will be liberated by 0.25 × 4×96500/1 = 96500 C

Therefore, 0.25 moles of oxygen is liberated by 96500 C