Answer:
Aubrey is correct because the area of the new parallelogram is 12 (6) = 72 square inches. The original area is 18 square inches. Since 4 (18) = 72, the new parallelogram has 4 times the area of the original.
Explanation:
A parallelogram with a base of 6 inches and height of 3 inches. A side has a length of 5 inches.
Aubrey is correct because the area of the new parallelogram is 12 (6) = 72 square inches. The original area is 18 square inches. Since 4 (18) = 72, the new parallelogram has 4 times the area of the original.
Aubrey is correct because the area of the new parallelogram is 10 (7) = 70 square inches. The original area is 18 square inches. Since 4 (18) = 72, it is about 4 times larger than the original.
Aubrey is incorrect because if one doubles each dimension, then the area will automatically be doubled as well. The original area is 18 square inches so the new parallelogram will have an area of 2 (18) = 36, or two times more than the original.
Aubrey is incorrect because if one doubles each dimension, then the area will automatically be doubled as well. The original area is 30 square inches so the new parallelogram will have an area of 2 (30) = 60, or 2 times more than the original.
Workings
Area of a parallelogram=base×height
Original parallelogram
Base=6 inches
Height=3 inches
Area=base×height
=6×3
=18 square inches
New parallelogram with doubled dimensions
Base=6 inches doubled=12 inches
Height=3 inches doubled=6 inches
Area=base×height
=12×6
=72 square inches
New area=4 times original area
New area=4×18
New area=72 square inches