Question

1)Un niño dispara una piedra con una honda, verticalmente hacia arriba, desde la planta baja de un edificio, con una velocidad de 10 m/s. Calcular: a)¿A qué altura máxima llega la piedra respecto del suelo? b)¿Qué velocidad tendrá la piedra al segundo de haber sido lanzada?

Answer 1

a) h_max = 5.10m

b) v = 0.2 m/s

Step-by-step explanation:

a) In order to calculate the maximum height reached by the rock, you use the following formula:

`h_(max)=(v_o^2)/(2g)` (1)

vo: initial speed of the rock = ?

g: gravitational acceleration constant = 9.8m/s^2

You replace the values of the parameters in the equation (1):

`h_(max)=((10m/s)^2)/(2(9.8m/s^2))=5.10m`

The maximum height reached by the rock is 5.10m

b) The speed of the rock, one second after it was thrown is given by:

`v=v_o-gt\\\\v=10m/s-(9.8m/s^2)(1s)=0.2(m)/(s)`

The speed of the rock is 0.2m/s