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If x, y, z, are integers such that 2^x*3^y*7^z=329, Then what is x, y, and z? PLZZZZ HELP THANK YOU
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If x, y, z, are integers such that 2^x*3^y*7^z=329, Then what is x, y, and z? PLZZZZ HELP THANK YOU

User Imran Arshad
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5 votes

Answer:

I just answered this question lol but the answer is 2^0*3^0*7^47=329. Hope this helps!!

Explanation:

User Jack James
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