Question

Express the confidence interval 0.333 less than p less than 0.999 in the form Modifying Above p with caret + or - E. Modifying Above p with caret + or - E = + or -.

Answer 1

We are being asked to express the confidence interval "
`0.333 < p < 0.999` " in the form
`P + / - E`. Well, just take a look at procedure below for the first half of the problem,

`P = ( 0.999 + 0.333 ) / 2,\\E = ( 0.999 - 0.333 ) / 2`

As you can see, for this first bit we took the average of the numbers, for the second we subtracted one from the other, and now let us approximate each value -

`P = ( About ) 0.666,\\E = ( About ) 0.333`

And so,
`P + / - E` should be
`0.666 + / - 0.333`. That is our solution!