Question

Find the lateral area of this pyramid whose base is a regular hexagon with a side length of 3cm and whose slant height is 12cm.

Answer 1

108 cm^2

Explanation:

The lateral surface area of a pyramid is given as

LSA= 1/2×perimeter of the base×slant height

base is hexagon with side 3 cm , therefore, perimeter of the base

=6×3=18 cm

slant height = 12 cm

thus, LSA = 1/2×18×12 = 108 cm^2