Answer:
See steps below on how to obtain the final solution
![x=2\\y=0](https://img.qammunity.org/2021/formulas/mathematics/high-school/cjtz4lw9eevxygdsixhwo8tzq55top75a7.png)
using Gauss elimination
Explanation:
Let's write this system with the equations swapped since we want the largest value for the x dependence in the top row:
![5x-y=10\\-3x+4y=-6](https://img.qammunity.org/2021/formulas/mathematics/college/5sy1xx6zpponh4ni8n5uty1vub2ds3a002.png)
Now let's scale the first equation by dividing it by 5 (the leading coefficient for x):
![x-(1)/(5) y=2\\-3x+4y=-6](https://img.qammunity.org/2021/formulas/mathematics/college/f6z0vkr71oxrzrexwgq7ch5f71f6t003rs.png)
now multiply row 1 by 3 and combine with row 2 :
![3\,x-(3)/(5) y=6\\-3x+4y=-6\\ \\0+(17)/(5) y=0](https://img.qammunity.org/2021/formulas/mathematics/college/l1bllbzx1yfrzoor8iimr2z7e9e480cs7r.png)
now replace the second row by this combination:
![x-(1)/(5) y=2\\0+(17)/(5) y=0](https://img.qammunity.org/2021/formulas/mathematics/college/rd89jve7r8v4t07plqas2trpda04zurxmz.png)
Now multiply the second row by 5/17:
![x-(1)/(5) y=2\\0+} y=0](https://img.qammunity.org/2021/formulas/mathematics/college/7khg59e1xe1gdcwxsyubx0pmk5so0sh5mn.png)
multiply the bottom row by 1/5 and combine with the first row to eliminate the term in y:
![x-(1)/(5) y=2\\0+(1)/(5) y=0\\ \\x-0=2](https://img.qammunity.org/2021/formulas/mathematics/college/i1e9d92zdrctt2tbsjiz2191dxac304a0d.png)
Now we have the answer to the system:
![x=2\\y=0](https://img.qammunity.org/2021/formulas/mathematics/high-school/cjtz4lw9eevxygdsixhwo8tzq55top75a7.png)