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What is the following product? (3 startroot 16x^7 endroot) (3 startroot 12x^9 endroot)

User Yurgis
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1 Answer

4 votes

Answer:

72x^8

Explanation:

Product of ;

3 √(16x^7) * 3 √(12x^9)

Let’s factor out all perfect squares in the roots

3 √(16 * x^4 * x^3) * 3 √(4 * 3 * x^8 * x)

Taking out the perfect squares, we have;

3 * 4 * x^2 * √(x^3) * 3 * 2 * √3 * x^4 * √(x)

72 * x^(2 + 4) * √(x^3 * x)

72 * x^6 * √(x^4)

72 * x^6 * x^2

72 * x^8

User Alexey Soshin
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