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A 5.0-Ω resistor and a 9.0-Ω resistor are connected in parallel. A 4.0-Ω resistor is then connected in series with this parallel combination. An ideal 6.0-V battery is then connected across the series-parallel combination of the three resistors. What is the current through (a) the 4.0-Ω resistor? (b) the 5.0-Ω resistor? (c) the 9.0-Ω resistor?

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Answer:

Step-by-step explanation:

The current through the resistor is 0.83 A

.

Part b

The current through resistor is 0.53 A

.

Part c

The current through resistor is 0.30 A

User Tushar Agarwal
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