Answer:
Not reject null hypothesis since the p value is greater than 0.05
Explanation:
We have the following:
z = (x ^ -m) / (sd / n ^ (1/2))
Let m be the mean that is 8, sd the standard deviation that is 0.6, n the sample size that is 32 and x the value to evaluate that is 8.2, replacing:
z = (8.2-8) / (0.6 / 32 ^ (1/2)) = 1.89
P (x> 8.2) = P (z> 1.89)
P (x> 8.2) = 1 - P (z <1.89)
We look for this value in the attached table of z and we have to:
P (x> 215) = 1 - 0.9713 (attached table)
P (x> 215) = 0.0287
since this is a two tailed test, the area of 0.0287 must be doubled the p value
the p value = 0.05794
Therefore, the decision is to not reject null hypothesis since the p value is greater than 0.05