Answer:
the speed of the block when it reaches point B is 14 m/s
Step-by-step explanation:
Given that:
mass of the block slides = 1.5 - kg
height = 10 m
Force constant = 200 N/m
distance of rough surface patch = 20 m
coefficient of kinetic friction = 0.15
In order to determine the speed of the block when it reaches point B.
We consider the equation for the energy conservation in the system which can be represented by:






v = 14 m/s
Thus; the speed of the block when it reaches point B is 14 m/s