Answer:
The value of the effective (rms) voltage of the applied source in the circuit is 132 V
Step-by-step explanation:
Given;
effective (rms) voltage of the resistor,
= 65 V
effective (rms) voltage of the inductor,
= 140 V
effective (rms) voltage of the capacitor,
= 80 V
Determine the value of the effective (rms) voltage of the applied source in the circuit;
![V= √(V_R^2 + (V_L^2-V_C^2) )\\\\V= √(65^2 + (140^2-80^2) )\\\\V = √(4225+ 13200) \\\\V = √(17425) \\\\V = 132 \ V](https://img.qammunity.org/2021/formulas/physics/college/7vfavyru71nul6vi8a7orh8nxbmiujv6ia.png)
Therefore, the value of the effective (rms) voltage of the applied source in the circuit is 132 V.