Answer:
Following are the answer to this question:
Step-by-step explanation:
Let,
A = Brenda is guilty.
B =Anthony is guilty.
C = Charles is guilty.
The Brenda says that If A then C:

The Anthony says that B and C are not:

The Charles syas that

In option a)
The propositional logic formula as follows:

follows are the given claims:

That's why the above code is false.
In option b)
In this option the given point is not contradictory because all three given point can't be satisfied.
In option c)
In this point A and C both were false because both lies that their claim are not satisfied.
In option d)
B equals to T, that's is A"Brenda is guilty".