Answer:
From the attached graph, the x-intercept is (13, 0)
Explanation:
The question equation is y = x³ + 11·x² - 312·x
To graph the equation, we find the value of y for a given value of x and we plot the values on a graph as follows;
x, y
13, 0
14, 532
15, 1170
16, 1920
17, 2788
18, 3780
19, 4902
20, 6160
21, 7560
22, 9108
23, 10810
24, 12672
25, 14700
From the graph, the x-intercept can be found at at x = 13.
The x-intercept can also be obtained by equating the right hand side of the equation to 0 (y = 0 is the x -intercept) as follows;
0 = x³ + 11·x² - 312·x
Therefore, x = 0 is one of the x-intercepts
By dividing by x, we have
x² + 11·x - 312 = 0
By completing the square we have
x² + 11·x + (11/2)² = 312+(11/2)²
(x + 11/2)² = 1369/4
x + 11/2 = ±37/2
x = 37/2 - 11/2 = 13 or x = -37/2 - 11/2 = -24
Which gives the x-intercept as (13, 0).