Question

Three numbers are in ration 3: 4: 8. The sum of the two larger numbers exceeds twice the smallest by 48. Find the numbers.

Answer 1

24, 32, 64

Explanation:

1st=3x

2nd=4x

3rd=8x

2(3x)+48=4x+8x

6x+48=12x

48=6x

x=8

SO:

1st =24

2nd= 32

3rd= 64

Answer 2

24, 32, 64

Explanation:

12x=6x+48

-6x -6x

6x=48

x=8

8(3)=24

8(4)=32

8(8)=64